问题:

【f(x)=根号3sin^2x+sinxcosx-根号3/2】

更新时间:2024-03-29 20:16:43

问题描述:

f(x)=根号3sin^2x+sinxcosx-根号3/2

马俊英回答:

  f(x)=根号3sin^2x+sinxcosx-根号3/2

  =sinxcosx-√3/2*(1-2sin²x)

  =(1/2)sin2x-(√3/2)cos2x

  =sin(2x)*cos(π/3)-cos(2x)sin(π/3)

  =sin(2x-π/3)