问题:
问题描述:
f(x)=根号3sin^2x+sinxcosx-根号3/2
马俊英回答:
=sinxcosx-√3/2*(1-2sin²x)
=(1/2)sin2x-(√3/2)cos2x
=sin(2x)*cos(π/3)-cos(2x)sin(π/3)
=sin(2x-π/3)